Lincoln Industrial Corp Company Information
Overview
Lincoln Industrial Corp is located in MO. Lincoln Industrial Corp mainly operate in the General Industrial Machinery, industry. Currently they have estimated 201–500 employees.
Website:
-
http://lincolnindustrial.com
Size:
-
201–500 employees
Headquarters:
- 5148 N Hanley Rd, MO 63134
Phone Number:
-
Fax
Industry:
-
General Industrial Machinery,
Founded:
-
1910
Employees at Lincoln Industrial Corp
Showing 10 of 243| JOB TITLE | WORK EMAIL | WORK PHONE | LOCATION | |
|---|---|---|---|---|
| Regional Sales Manager Western Division | Denver, Colorado | |||
| Employee | St-Louis, Saint-Louis | |||
| National Account Manager Aftermarket Distribution | Kansas City, Missouri | |||
| Advertising and Web Manager | Saint Louis, Missouri | |||
| Manufacturing Ops Coordinator and Executive Assistant To Vice President Manufacturing | St-Louis, Saint-Louis | |||
| Vice President Of Sales and Marketing | St-Louis, Saint-Louis | |||
| District Manager | Seattle, Washington | |||
| Vice President and Cfo | St-Louis, Saint-Louis | |||
| Vice President Operations | Saint Louis, Missouri | |||
| Internship | Stuttgart, Bayern |
Regional Sales Manager Western Division
Denver, Colorado 
Employee
St-Louis, Saint-Louis
National Account Manager Aftermarket Distribution
Kansas City, Missouri
Advertising and Web Manager
Saint Louis, Missouri
Manufacturing Ops Coordinator and Executive Assistant To Vice President Manufacturing
St-Louis, Saint-Louis
Vice President Of Sales and Marketing
St-Louis, Saint-Louis
District Manager
Seattle, Washington
Vice President and Cfo
St-Louis, Saint-Louis
Vice President Operations
Saint Louis, Missouri
Internship
Stuttgart, Bayern
Enter an employee name to search and verify work emails, phone numbers and social links etc.
Lincoln Industrial Corp's Email Format
We found 5 email formats used by Lincoln Industrial Corp employees. The most common Lincoln Industrial Corp email format is first_initial last ex.(jdoe@lincolnindustrial.com) being used 85% of the time.
first_initial last
85%
first_initial.last
5%
last
5%
others
3%
first last
1%
