Palmetto Health Company Information
Overview
Palmetto Health is located in SC. Palmetto Health mainly operate in the Hospitals industry. Currently they have estimated 5,001–10,000 employees.
Website:
-
http://palmettohealth.org
Size:
-
5,001–10,000 employees
Headquarters:
- 200 Fleetwood Dr, SC 29640
Phone Number:
-
Fax
Industry:
-
Hospitals
Founded:
-
1998
Employees at Palmetto Health
Showing 10 of 3483| JOB TITLE | WORK EMAIL | WORK PHONE | LOCATION | |
|---|---|---|---|---|
| Executive Vice President and Coo Palmetto Health Richland | Columbia, South Carolina | |||
| System Vice President, Human Resources | Columbia, South Carolina | |||
| Executive Vice President and Ceo | Cayce, South Carolina | |||
| Vice President, Clinical Quality and Patient Safet | Columbia, South Carolina | |||
| Cto | Emmons, West Virginia | |||
| Executive Vice President and Cfo At Palmetto Health | Columbia, South Carolina | |||
| Employee | Columbia, South Carolina | |||
| Vice President Orthopedic Services | Columbia, South Carolina | |||
| Vice President | Columbia, South Carolina | |||
| Corporate Director Of Applications | Louisville, Kentucky |
Executive Vice President and Coo Palmetto Health Richland
Columbia, South Carolina 
System Vice President, Human Resources
Columbia, South Carolina
Executive Vice President and Ceo
Cayce, South Carolina
Vice President, Clinical Quality and Patient Safet
Columbia, South Carolina
Cto
Emmons, West Virginia
Executive Vice President and Cfo At Palmetto Health
Columbia, South Carolina
Employee
Columbia, South Carolina
Vice President Orthopedic Services
Columbia, South Carolina
Vice President
Columbia, South Carolina
Corporate Director Of Applications
Louisville, Kentucky
Enter an employee name to search and verify work emails, phone numbers and social links etc.
Palmetto Health's Email Format
We found 4 email formats used by Palmetto Health employees. The most common Palmetto Health email format is first.last ex.(jane.doe@palmettohealth.org) being used 87% of the time.
first.last
87%
others
7%
first_initial.last
1%
last
1%
